Who will last?

[AuburnAttack21]

Today in Chemistry I started working out this equation:

253/0=%5*$-[eb#(-!3d

I think the next place is either $ or @. Anyone care to help me out on this one?

Well let's see...bringing over the 3 would mean...subtract ! from # and you get @...multiply the ] and...

If the 3rd place is * then the seventeenth must be ^. Add the (%x() and you get $b!^ so that means the fourteenth place is $.

Hmm.

Then that would carry the @ over and leave the eighteenth place to be &...which means the nineteenth place is either (, ), or ;.

[ucan]

[AuburnAttack21]

So if the nineteenth is ( then that would lead to the twentieth being (, which can't be right. If it was ) the 20th would either be u or %, most likely u if the tenth place is (. But then if you multiply ^ by ! you get ), and then adding the # would be ;, so the nineteenth place is ;, and the 20th is certainly ], no doubt.

253/0=%5*$-[eb#(-!3$b!^&;]

It definitely looks right but at the same time it doesn't...

[ucan]

[AuburnAttack21]

Ah, that's right, I forgot to add the !@$%.

That means the 25th and 26th places are - and y, and the 27th place is q, which then means the next four are *, 7, , and . Which wuld also mean the 31st place is + and the 32nd would therefore be g.

Perfect.

253/0=%5*$-[eb#(-!3$b!^&;]!@$%-yq*7,.+g

[Sublimity]

Wanna make my mathematics test?

[selocon]

lol i need a stanbd in for my algebra sol in may..or june

[NothingPersonal]

[youtube:221px336][/youtube:221px336]

[Riykku]

[youtube:1hv54ugl]rx8zMBQaZjQ[/youtube:1hv54ugl]

[hidude1212]

what does meme mean?