Well let's see...bringing over the 3 would mean...subtract ! from # and you get @...multiply the ] and...Originally Posted by AuburnAttack21
If the 3rd place is * then the seventeenth must be ^. Add the (%x() and you get $b!^ so that means the fourteenth place is $.
Hmm.
Then that would carry the @ over and leave the eighteenth place to be &...which means the nineteenth place is either (, ), or ;.